Optimal. Leaf size=141 \[ \frac{2 a^2 \cos ^7(c+d x)}{7 d}-\frac{2 a^2 \cos ^5(c+d x)}{5 d}-\frac{a^2 \sin ^3(c+d x) \cos ^5(c+d x)}{8 d}-\frac{11 a^2 \sin (c+d x) \cos ^5(c+d x)}{48 d}+\frac{11 a^2 \sin (c+d x) \cos ^3(c+d x)}{192 d}+\frac{11 a^2 \sin (c+d x) \cos (c+d x)}{128 d}+\frac{11 a^2 x}{128} \]
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Rubi [A] time = 0.257826, antiderivative size = 141, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 6, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.207, Rules used = {2873, 2568, 2635, 8, 2565, 14} \[ \frac{2 a^2 \cos ^7(c+d x)}{7 d}-\frac{2 a^2 \cos ^5(c+d x)}{5 d}-\frac{a^2 \sin ^3(c+d x) \cos ^5(c+d x)}{8 d}-\frac{11 a^2 \sin (c+d x) \cos ^5(c+d x)}{48 d}+\frac{11 a^2 \sin (c+d x) \cos ^3(c+d x)}{192 d}+\frac{11 a^2 \sin (c+d x) \cos (c+d x)}{128 d}+\frac{11 a^2 x}{128} \]
Antiderivative was successfully verified.
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Rule 2873
Rule 2568
Rule 2635
Rule 8
Rule 2565
Rule 14
Rubi steps
\begin{align*} \int \cos ^4(c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^2 \, dx &=\int \left (a^2 \cos ^4(c+d x) \sin ^2(c+d x)+2 a^2 \cos ^4(c+d x) \sin ^3(c+d x)+a^2 \cos ^4(c+d x) \sin ^4(c+d x)\right ) \, dx\\ &=a^2 \int \cos ^4(c+d x) \sin ^2(c+d x) \, dx+a^2 \int \cos ^4(c+d x) \sin ^4(c+d x) \, dx+\left (2 a^2\right ) \int \cos ^4(c+d x) \sin ^3(c+d x) \, dx\\ &=-\frac{a^2 \cos ^5(c+d x) \sin (c+d x)}{6 d}-\frac{a^2 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{6} a^2 \int \cos ^4(c+d x) \, dx+\frac{1}{8} \left (3 a^2\right ) \int \cos ^4(c+d x) \sin ^2(c+d x) \, dx-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int x^4 \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=\frac{a^2 \cos ^3(c+d x) \sin (c+d x)}{24 d}-\frac{11 a^2 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{a^2 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{16} a^2 \int \cos ^4(c+d x) \, dx+\frac{1}{8} a^2 \int \cos ^2(c+d x) \, dx-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \left (x^4-x^6\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{2 a^2 \cos ^5(c+d x)}{5 d}+\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{a^2 \cos (c+d x) \sin (c+d x)}{16 d}+\frac{11 a^2 \cos ^3(c+d x) \sin (c+d x)}{192 d}-\frac{11 a^2 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{a^2 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{64} \left (3 a^2\right ) \int \cos ^2(c+d x) \, dx+\frac{1}{16} a^2 \int 1 \, dx\\ &=\frac{a^2 x}{16}-\frac{2 a^2 \cos ^5(c+d x)}{5 d}+\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{11 a^2 \cos (c+d x) \sin (c+d x)}{128 d}+\frac{11 a^2 \cos ^3(c+d x) \sin (c+d x)}{192 d}-\frac{11 a^2 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{a^2 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{128} \left (3 a^2\right ) \int 1 \, dx\\ &=\frac{11 a^2 x}{128}-\frac{2 a^2 \cos ^5(c+d x)}{5 d}+\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{11 a^2 \cos (c+d x) \sin (c+d x)}{128 d}+\frac{11 a^2 \cos ^3(c+d x) \sin (c+d x)}{192 d}-\frac{11 a^2 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{a^2 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}\\ \end{align*}
Mathematica [A] time = 0.500808, size = 96, normalized size = 0.68 \[ \frac{a^2 (1680 \sin (2 (c+d x))-2520 \sin (4 (c+d x))-560 \sin (6 (c+d x))+105 \sin (8 (c+d x))-10080 \cos (c+d x)-3360 \cos (3 (c+d x))+672 \cos (5 (c+d x))+480 \cos (7 (c+d x))+3360 c+9240 d x)}{107520 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.039, size = 164, normalized size = 1.2 \begin{align*}{\frac{1}{d} \left ({a}^{2} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{8}}-{\frac{\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{16}}+{\frac{\sin \left ( dx+c \right ) }{64} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{128}}+{\frac{3\,c}{128}} \right ) +2\,{a}^{2} \left ( -1/7\, \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{5}-{\frac{2\, \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{35}} \right ) +{a}^{2} \left ( -{\frac{\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{6}}+{\frac{\sin \left ( dx+c \right ) }{24} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{dx}{16}}+{\frac{c}{16}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.07777, size = 138, normalized size = 0.98 \begin{align*} \frac{6144 \,{\left (5 \, \cos \left (d x + c\right )^{7} - 7 \, \cos \left (d x + c\right )^{5}\right )} a^{2} + 560 \,{\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 12 \, d x + 12 \, c - 3 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} + 105 \,{\left (24 \, d x + 24 \, c + \sin \left (8 \, d x + 8 \, c\right ) - 8 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2}}{107520 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.57593, size = 258, normalized size = 1.83 \begin{align*} \frac{3840 \, a^{2} \cos \left (d x + c\right )^{7} - 5376 \, a^{2} \cos \left (d x + c\right )^{5} + 1155 \, a^{2} d x + 35 \,{\left (48 \, a^{2} \cos \left (d x + c\right )^{7} - 136 \, a^{2} \cos \left (d x + c\right )^{5} + 22 \, a^{2} \cos \left (d x + c\right )^{3} + 33 \, a^{2} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{13440 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 12.6969, size = 420, normalized size = 2.98 \begin{align*} \begin{cases} \frac{3 a^{2} x \sin ^{8}{\left (c + d x \right )}}{128} + \frac{3 a^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{32} + \frac{a^{2} x \sin ^{6}{\left (c + d x \right )}}{16} + \frac{9 a^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{64} + \frac{3 a^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac{3 a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{32} + \frac{3 a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{16} + \frac{3 a^{2} x \cos ^{8}{\left (c + d x \right )}}{128} + \frac{a^{2} x \cos ^{6}{\left (c + d x \right )}}{16} + \frac{3 a^{2} \sin ^{7}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{128 d} + \frac{11 a^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{128 d} + \frac{a^{2} \sin ^{5}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{16 d} - \frac{11 a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{128 d} + \frac{a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{6 d} - \frac{2 a^{2} \sin ^{2}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac{3 a^{2} \sin{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} - \frac{a^{2} \sin{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{16 d} - \frac{4 a^{2} \cos ^{7}{\left (c + d x \right )}}{35 d} & \text{for}\: d \neq 0 \\x \left (a \sin{\left (c \right )} + a\right )^{2} \sin ^{2}{\left (c \right )} \cos ^{4}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.43746, size = 189, normalized size = 1.34 \begin{align*} \frac{11}{128} \, a^{2} x + \frac{a^{2} \cos \left (7 \, d x + 7 \, c\right )}{224 \, d} + \frac{a^{2} \cos \left (5 \, d x + 5 \, c\right )}{160 \, d} - \frac{a^{2} \cos \left (3 \, d x + 3 \, c\right )}{32 \, d} - \frac{3 \, a^{2} \cos \left (d x + c\right )}{32 \, d} + \frac{a^{2} \sin \left (8 \, d x + 8 \, c\right )}{1024 \, d} - \frac{a^{2} \sin \left (6 \, d x + 6 \, c\right )}{192 \, d} - \frac{3 \, a^{2} \sin \left (4 \, d x + 4 \, c\right )}{128 \, d} + \frac{a^{2} \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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